Phương pháp giải:

Lời giải chi tiết:

$\left\{ \matrix{ BaO:1 \hfill \cr CuO:1 \hfill \cr F{e_2}{O_3}:1 \hfill \cr A{l_2}{O_3}:1 \hfill \cr} \right.\buildrel { + CO\,du} \over \longrightarrow \left\{ \matrix{ \uparrow A\left\{ \matrix{ CO\,du \hfill \cr C{O_2}:4 \hfill \cr} \right.\buildrel { + Ba(AlO2)2} \over \longrightarrow \left\{ \matrix{ \downarrow H:\,Al{(OH)_{3\,}}:2 \hfill \cr {\rm{dd}}\,G:\,Ba{(HC{O_3})_2}:1 \hfill \cr} \right. \hfill \cr ran\,B\left\{ \matrix{ BaO:1 \hfill \cr Cu:1 \hfill \cr Fe:2 \hfill \cr A{l_2}{O_3}:1 \hfill \cr} \right.\buildrel { + H2O\,du} \over \longrightarrow \left\{ \matrix{ {\rm{dd}}\,C:\,Ba{(Al{O_2})_2}:\,1 \hfill \cr ran\,D\left\{ \matrix{ Cu:1 \hfill \cr Fe:2 \hfill \cr} \right.\buildrel {{H_2}S{O_4},\,dac,\,{t^o}\,,du} \over \longrightarrow \uparrow S{O_2} \hfill \cr} \right. \hfill \cr} \right.$

$\eqalign{ & CuO{\rm{ }} + {\rm{ }}CO\buildrel {{t^o}} \over \longrightarrow Cu{\rm{ }} + {\rm{ }}H2O \uparrow \cr & F{e_2}{O_3} + {\rm{ }}3CO\buildrel {{t^o}} \over \longrightarrow 2Fe{\rm{ }} + {\rm{ }}3C{O_2} \uparrow \cr & 2C{O_2} + {\rm{ }}Ba{(Al{O_2})_2} + {\rm{ }}4{H_2}O{\rm{ }} \to {\rm{ }}Ba{(HC{O_3})_2} + {\rm{ }}2Al{\left( {OH} \right)_3} \downarrow \cr & BaO{\rm{ }} + {\rm{ }}{H_2}O{\rm{ }} \to {\rm{ }}Ba{\left( {OH} \right)_2} \cr & Ba{\left( {OH} \right)_2} + {\rm{ }}A{l_2}{O_3} \to {\rm{ }}Ba{(Al{O_2})_2} + {\rm{ }}{H_2}O \cr & Cu{\rm{ }} + {\rm{ }}2{H_2}S{O_4} \to {\rm{ }}CuS{O_4} + {\rm{ }}S{O_2} \uparrow {\rm{ }} + {\rm{ }}2{H_2}O \cr & 2Fe{\rm{ }} + {\rm{ }}6{H_2}S{O_4} \to {\rm{ }}F{e_2}{(S{O_4})_3} + {\rm{ }}3S{O_2} \uparrow {\rm{ }} + {\rm{ }}6{H_2}O \cr}$