Tính $\mathop {\lim }\limits_{n \to + \infty } \frac{1}{{{n^2} + 1}}.$
Tính $\mathop {\lim }\limits_{n \to + \infty } \frac{1}{{{n^2} + 1}}.$
-
A.
1.
-
B.
$ + \infty .$
-
C.
$ - \infty .$
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D.
0.
Ta có: \(\mathop {\lim }\limits_{x \to + \infty } 1 = 1\); \(\mathop {\lim }\limits_{x \to + \infty } ({n^2} + 1) = + \infty \).
Suy ra: \(\mathop {\lim }\limits_{x \to + \infty } \frac{1}{{{n^2} + 1}} = 0\).
Đáp án : D










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