Cho các giới hạn \(\mathop {\lim }\limits_{x \to {x_0}} f\left( x \right) = 1\),\(\mathop {\lim }\limits_{x \to {x_0}} g\left( x \right) = 4\).Tính
\(\mathop {\lim }\limits_{x \to {x_0}} \left[ {f\left( x \right) + 2g\left( x \right)} \right]\)
Nếu \(\mathop {\lim }\limits_{x \to {x_0}} f\left( x \right) = L,\mathop {\lim }\limits_{x \to {x_0}} g\left( x \right) = M\)thì:
\(\mathop {\lim }\limits_{x \to {x_0}} \left[ {f\left( x \right) \pm g\left( x \right)} \right] = L \pm M\)
\(\mathop {\lim }\limits_{x \to {x_0}} c.f\left( x \right) = c.L\)
\(2g(x){\rm{] = }}\mathop {\lim }\limits_{x \to {x_0}} f\left( x \right) + \mathop {\lim }\limits_{x \to {x_0}} 2g\left( x \right) = 1 + 2.4 = 9\)
Đáp án : C

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